r.m.s. value of current `i=3+4 sin (omega t+pi//3)` is:A. `5 A`B. `sqrt17 A`C. `5/sqrt2 A`D. `7/sqrt2 A`

r.m.s. value of current `i=3+4 sin (omega t+pi//3)` is:A. `5 A`B. `sqr

1.	r.m.s. value of current `i=3+4 sin (omega t+pi//3)` is:A. `5 A`B. `sqrt17 A`C. `5/sqrt2 A`D. `7/sqrt2 A`
Answer» Correct Answer - B `I_(rms)=[(underset(0)overset(T)inti^(2)dt)/T]^(1/2)=[underset(0)overset(T)int[(3+4sin(omegat+pi//3))]^(2)/Tdt]^(1//2)=sqrt17`

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r.m.s. value of current `i=3+4 sin (omega t+pi//3)` is:A. `5 A`B. `sqrt17 A`C. `5/sqrt2 A`D. `7/sqrt2 A`

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