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InterviewSolution
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Radiant energy is incident on a body at the rate of 1000 joules per minute.If the reflection coefficient of the body is 0.2 and its transmission coefficient is 0.3, find the radiant energy (i) absorbed (ii) reflected (iii) transmitted by the body in 3 minutes. |
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Answer» Solution :a+ r+t=1a= 1 - r -t = 1-0.2 -0.3= 0.5 ` Let Q_(a) , Q_(r)and Q_(t)` bet the QUANTITIES of radiant energy absorbed, reflected and transmitted in 3 MINUTES by the body, RESPECTIVELY. (i) ` a = Q_(a)/Q "" therefore Q_(a) = aQ = 0.5 xx 3000 = 1500 J` (ii) ` r = Q_(r)/Q "" thereforeQ_(r) = rQ = 0.2 xx 3000= 600J` ` (III) t = (Q_t)/Q "" thereforeQ_(t_) = tQ = 0.3 xx 3000 = 900 J` |
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