Radioactive disintegration isa first order reaction and it's rate depends only upon the nature of nucleus and does not depend upon external factors like temperature and pressure . The rate of radioactive disintegration (Activity) is represented as - (dN)/(dt) = lambda N , Where lambda = decay constant , N number of nuclei at time t, N_(0) = initial no. of nuclei. The above equation after integration can be represented as lambda = (2.303)/(t) "log" ((N_(0))/(N)) Calculate the half-life period of a radioactive element which remains only 1/16 of it's original amount in 4740 years :

Radioactive disintegration isa first order reaction and it's rate depe

1.	Radioactive disintegration isa first order reaction and it's rate depends only upon the nature of nucleus and does not depend upon external factors like temperature and pressure . The rate of radioactive disintegration (Activity) is represented as - (dN)/(dt) = lambda N , Where lambda = decay constant , N number of nuclei at time t, N_(0) = initial no. of nuclei. The above equation after integration can be represented as lambda = (2.303)/(t) "log" ((N_(0))/(N)) Calculate the half-life period of a radioactive element which remains only 1/16 of it's original amount in 4740 years :
Answer» 1185 YEARS 2370 years 52.5 years none of these SOLUTION :`N_(0) to (N_(0))/(2) to (N_(0))/(4) to (N_(0))/(8) to (N_(0))/(16) , t = 4740 = 4 xx t_(1//2) , t_(1//2) = (4740)/(4) = 1185`