InterviewSolution
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InterviewSolution
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Radioactive disintergation always follow `I` order kinetics and is independent of all external factors and is represented by the relation `N = N_(0) e^(-lambda t)` where `lambda` is decay constant and `N` atoms are left at time `t`. The radioactive nature of element is expressed in terms of average life numerically equal to decay constant `(1//lambda)` however all the radioactive do not lose their radioactive nature in thier average life. The radioactive emission involves `alpha, beta` particles as well as `gamma-` rays.The penertrating power order is `alpha lt beta lt gamma`. The emissions can perntrate even thick steel walls but are however unable to penttrate `Pb` blocks. The `S` unit fo rate of decay is `dps`. The percentage of atoms decayed in average life of a radioactive element is:A. `36.78%`B. `63.22%`C. `3.678%`D. `6.322%` |
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Answer» Correct Answer - `d` `t = (2.303)/(lambda) log (N_(0))/(N)`, `:. (1)/(lambda) = (2.303)/(lambda) log (N_(0))/(N), (t = t_(av.) = (1)/(lambda))` `:. (N_(0))/(N) = 2.71` or `N = 0.3678xx N_(0) = 36.78%` `:.` decayed `= 100 - 36.78 = 63.28` |
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