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| 1. |
Radioactive lead ._(82)Pb^(201) has a half-life of 8 hours. Starting from one milligram of this isotope, how much will remain after 24 hours |
| Answer» Solution :`n = (24)/(8) = 3, N = (N_(0))/(2^(n)) = (1)/(2^(3)) = (1)/(8) mg` | |