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radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm what is the length of the chord? |
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Answer» 49.34 cm is the required length of the chord .According to the QUESTIONIT is given that ,Radius of circle OA = 25cmDistance of its Chord from the centre ,BO =4cmwe need to calculate the length of the Chord.So ,We will use here the Pythagoras THEOREM .AO² = BO² + AB²Substitute the value we get➻ 25² = 4² + AB²➻ 625 = 16 + AB²➻ 625-16 = AB²➻ 609 = AB²➻ AB = √609➻ AB = 24.67cmAs we KNOW that distance of its Chord from the the centre is PERPENDICULAR bisector of the chord .So, the length of the chord is twice AB➻ Length of Chord = 2AB➻ Length of Chord = 2×24.67➻ Length of Chord = 49.34 cmHence, the length of the chord is 49.34 cm (approx) |
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