1.

Radius of curvature of concave mirrorr is `40cm` and the size of image is twice as that of object, then the object distance isA. `60cm`B. `20cm`C. `40cm`D. `30cm`

Answer» Correct Answer - D
`f=(R)/(2)=20cm m=2` For real image`,m=-2`
Now, `m=(f)/(f-u)implies-2=(-20)/(-20-u)impliesu=-30cm`
For virtual image `,m=+2`
So, `+2=(-20)/(20-u)impliesu=-10cm`


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