1.

Radon has 3.8 days as its half-life . How much radon will be left out of 15 mg mass after 38 days ?

Answer»

1.05mg
0.015 mg
0.231 mg
0.50 mg

Solution :Here, `N=1/T_(1//2)=38/3.8=10`
`N=N_0(1/2)^n=m=m_0(1/2)^n =15 mg XX (1/2)^10`
`=15/1024`=0.015 mg


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