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Rae law for the reaction A+2BtoC is found to be Rate =K[A][B] concentration of reactant .B. is doubled ,keeping the concentration of .A. constant ,the value of rate constant will be…… |
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Answer» the same If the concentration of B is double than new concentration [2B] So `r_(2)`=k[A][B]=2K [A][B] `therefore (r_(2))/(r_(1))=2` so the rate is double |
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