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InterviewSolution
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Rahim removes all the hearts from the cards. What is the probability of i. Picking out an ace from the remaining pack. ii. Picking out a diamond. iii. Picking out a card that is not a heart. |
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Answer» Total number of cards in the deck = 52. Total number of hearts in the deck of cards =13. When Hearts are removed, remaining cards = 52 – 13 = 39. i)Picking out an Ace: Number of outcomes favourable to Ace = 3 [∵ ♦ A, ♥ A, ♠ A, ♣ A] Total number of possible outcomes from the remaining cards = 39 – after removing Hearts. Probability = P(A) \(=\frac{No.\,of\,favourable \,outcomes}{Total\, no.\,of \,outcomes}\) \(=\frac{3}{39}= \frac{1}{13}\) ii) Picking out a diamond: Number of favourable outcomes to diamonds (♦) = 13 Total number of possible outcomes = 39 ∴ p(♦) \(=\frac{3}{39}= \frac{1}{13}\) iii) Picking out a card that is ‘not a heart’: As all hearts are removed, the remain-ing cards are all non-heart cards. So the picked card will be definitely a non-heart card. So this is a sure event. Hence its probability is one P(E) \(=\frac{39}{39}= 1\) |
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