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Rain is falling vertically with a speed of 1 ms^(-1) . A woman rides a bicycle with a speed of 1.732 ms^(-1) is in east to west direction. What is the direction in which she should hold her umbrella? |
Answer» Solution : In Fig. `V_(t)` represents the VELOCITY of rain and `v_(b)` the velocity of the BICYCLE, the woman is RIDING. Both these velocities are with respect to the ground. Since the woman is riding a bicycle, the velocity of rain as experienced by  her is the velocity of rain relative to the velocity of the bicycle she is riding. That is `V_(rb)=V_(t)-V_(b)` This relative velocity vector as shown in Fig. makes an angle `theta` with the vertical. It is given by `"tan" theta=(v_(b))/(v_(r))= (sqrt(3))/(1)= sqrt(3)=60^(@)` Therefore, the woman should hold her umbrella at an angle of about `60^(@)` with the vertical towards the WEST. |
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