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Ram ans Shyam purchased two electric tea kettles A and B of same size, same thickness, and same volume of 0.4L. They studied the specification of kettles as under Kettle A: specific heat capacity = 1680 Jkg^(-1)K^(-1) Mass = 200 g Cost = Rs. 400 Kettle B: Specific heat capacity= 2450 Jkg^(-1) K^(-1) Mass = 400 g Cost = Rs. 400 When kettle A is switched on with constant potential source, the tea begins to boil in 6 min. When kettle B is switched on with the same source separately, then tea begins to boil in 8 min. The efficiengy of kettle is defined as (Energy used for liquid heating)/(Total energy supplied) They made discussion on specification and efficiency of kettles and subsequently prepared a list of questions to draw the conclusions. Some of them are as under (assume specific heat of tea liquid as 4200J kg^(-1)K^(-1) and density 1000 kgm^(-3) If both the kettles are joined with the same source in series one after the other, then boiling starts in kettle A and kettle B after |
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Answer» FOUR times of their original time But `R_(A) = R_(B) or V^2/R_(A) xx 6 = V^2/R_(A) xx 6 = V^2/(4R_(A)^(2)) R_(A) xx t_(A)` `t_(A) = 24min.` (ii) `V^2/R_(B) xx 8 = V^2/(R_(A)+R_(B))^2 R_(B) xx t_(B)` `8/R_(B) = R_(B)/(4R_(B^2)) t_(B) or t_(B) = 32min.` |
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