1.

Ram ans Shyam purchased two electric tea kettles A and B of same size, same thickness, and same volume of 0.4L. They studied the specification of kettles as under Kettle A: specific heat capacity = 1680 Jkg^(-1)K^(-1) Mass = 200 g Cost = Rs. 400 Kettle B: Specific heat capacity= 2450 Jkg^(-1) K^(-1) Mass = 400 g Cost = Rs. 400 When kettle A is switched on with constant potential source, the tea begins to boil in 6 min. When kettle B is switched on with the same source separately, then tea begins to boil in 8 min. The efficiengy of kettle is defined as (Energy used for liquid heating)/(Total energy supplied) They made discussion on specification and efficiency of kettles and subsequently prepared a list of questions to draw the conclusions. Some of them are as under (assume specific heat of tea liquid as 4200J kg^(-1)K^(-1) and density 1000 kgm^(-3) If both the kettles are joined with the same source in series one after the other, then boiling starts in kettle A and kettle B after

Answer»

FOUR times of their original time
equal to their original time
two times of their original time
cannot be ASCERTAINED by above DATA.

Solution :a. (i) `V^2/R_(A) xx 6 = V^2/(R_A + R_(B))^2 R_(A) xx t_(A)`
But `R_(A) = R_(B) or V^2/R_(A) xx 6 = V^2/R_(A) xx 6 = V^2/(4R_(A)^(2)) R_(A) xx t_(A)`
`t_(A) = 24min.`
(ii) `V^2/R_(B) xx 8 = V^2/(R_(A)+R_(B))^2 R_(B) xx t_(B)`
`8/R_(B) = R_(B)/(4R_(B^2)) t_(B) or t_(B) = 32min.`


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