1.

Ramesh and Suresh earn Rs. x and Rs. y respectively. Ramesh spends 60% of his earning on rent and utilities, 80% of the remaining for food, Rs 360 for buying a shirt and saves the remaining money. Suresh spends 75% of his earning on rent and utilities, 90% of the remaining for food, Rs 75 for buying a hat and saves the remaining. If the savings of Ramesh is 100% more than the savings of Suresh and their sum of their salaries is Rs 27000, what is the value of x?1). 120002). 150003). 180004). 11000

Answer»

Amount SPENT by Ramesh on rent and utilities = 60/100 × x = 0.6x

⇒ Remaining amount LEFT = x – 0.6x = 0.4x

⇒ Amount spent by Ramesh on food = 80/100 × 0.4x = 0.32x

⇒ Remaining amount left = 0.4x – 0.32x = 0.08x

⇒ Remaining amount after buying a shirt = Savings = 0.08x – 360

⇒ Amount spent by SURESH on rent and utilities = 75/100 × y = 0.75y

⇒ Remaining amount left = y – 0.75y = 0.25y

⇒ Amount spent by Suresh on food = 90/100 × 0.25y = 0.225y

⇒ Remaining amount left = 0.25y – 0.225y = 0.025y

⇒ Remaining amount after buying a hat = Savings = 0.025y – 75

Given that the saving of Ramesh is 100% more than that of Suresh i.e. twice that of Suresh

⇒ 0.08x – 360 = 2 × (0.025y – 75)

⇒ 0.08x – 0.05y = 210---- (1)

⇒ Total salary received = x + y = 27000---- (2)

SOLVING we get x = 12000 and y = 15000


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