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Range ofthe function `f(x)=cos(Ksin x)` is `[-1,1]`, then the least positive integral value of K will beA. 1B. 2C. 3D. 4 |
Answer» Correct Answer - D `y=cos(K sinx)` `(cos^(-1)y)/(K)=sinx` `implies -1 le (cos^(-1)y)/(K) le 1` `implies -K le cos^(-1)y le K` Now `cos ^(-1) y in [0,pi]` `implies K=4` |
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