1.

Range ofthe function `f(x)=cos(Ksin x)` is `[-1,1]`, then the least positive integral value of K will beA. 1B. 2C. 3D. 4

Answer» Correct Answer - D
`y=cos(K sinx)`
`(cos^(-1)y)/(K)=sinx`
`implies -1 le (cos^(-1)y)/(K) le 1`
`implies -K le cos^(-1)y le K`
Now `cos ^(-1) y in [0,pi]`
`implies K=4`


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