Ratan smashes 86 runs against his opposite team in 16 balls. If he onl

1.	Ratan smashes 86 runs against his opposite team in 16 balls. If he only scored in boundaries (fouRs. and sixes), then find the maximum percent of runs he scored by hitting fours.1. 26.25%2. 23.25%3. 30%4. 28%
Answer» Correct Answer - Option 2 : 23.25% Given: Ratan scored his runs only in boundaries. Total balls played = 16 Total runs = 86 Calculations: Ratan scored his runs only in boundaries. Let the number of fouRs. be x and the number of sixes be y. Total balls played = 16 ⇒ x + y = 16 ⇒ x = 16 – y ----(1) Total runs = 86 ⇒ 4x + 6y = 86 ----(2) Put value of x from equ. (1) to eq. (2) ⇒ 4(16 – y) + 6y = 86 ⇒ 64 – 4y + 6y = 86 ⇒ 2y = 22 ⇒ y = 11 From eq. (1) x = 16 – 11 = 5 x = 5 and y = 11 Runs scored in the boundaries i.e fouRs. = 4 × 5 = 20 Percentage of runs scored in fouRs. = (20/86) × 100 = 23.25% ∴ The maximum percent of runs he scored by hitting fouRs. is 23.25%.

Ratan smashes 86 runs against his opposite team in 16 balls. If he only scored in boundaries (fouRs. and sixes), then find the maximum percent of runs he scored by hitting fours.1. 26.25%2. 23.25%3. 30%4. 28%

Answer» Correct Answer - Option 2 : 23.25%

Given:

Ratan scored his runs only in boundaries.

Total balls played = 16

Total runs = 86

Calculations:

Ratan scored his runs only in boundaries.

Let the number of fouRs. be x and the number of sixes be y.

Total balls played = 16

⇒ x + y = 16

⇒ x = 16 – y ----(1)

Total runs = 86

⇒ 4x + 6y = 86 ----(2)

Put value of x from equ. (1) to eq. (2)

⇒ 4(16 – y) + 6y = 86

⇒ 64 – 4y + 6y = 86

⇒ 2y = 22

⇒ y = 11

From eq. (1)

x = 16 – 11 = 5

x = 5 and y = 11

Runs scored in the boundaries i.e fouRs. = 4 × 5 = 20

Percentage of runs scored in fouRs. = (20/86) × 100 = 23.25%

∴ The maximum percent of runs he scored by hitting fouRs. is 23.25%.

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