1.

Rate constant for a reaction varies with temperature as, ln K(sec^(-1))=14.34-(1.25xx10^(4))/(T) Which statement(s) is (are) correct?

Answer»

(a) The graph plotted `log_(10) K` vs. `1/T` is straight LINE with `E_(a)=24.83 KCAL`
(B) Pre-exponential factor`=13.34`
(c ) The rate constant at `500 K` is `2.35xx10^(-5) sec^(-1)`
(d) `E_(a)=30.63 kcal`

Solution :N//A


Discussion

No Comment Found

Related InterviewSolutions