1.

Rate constant k for first order reaction has been found to be 2.54xx10^(-3)s^(-1). Calculate its three-fourth time.

Answer»

Solution :For the first ORDER reaction, use the relation
`k=(2.303)/(t)"log"([R]_(0))/([R])`
For three-foursth of the reaction to take place, `[R]=([R]_(0))/(4)or ([R]_(0))/([R])=4`
Substituting the values in the rate equation, we have
`2.54xx10^(-3)=(2.303)/(t)LOG4`
or `t=(2.303)/(2.54)xx10^(3)xx0.6021=5.46xx10^(2)s`


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