1.

Rate constant of a first order reaction A products is 0.016 min^(-1). Calculate the time required for 80% of the reaction to be completed.

Answer»

SOLUTION :`K = (2.303)/(t) LOG.(a)/(a-x)`
`t = (2.303)/(0.016)log.(100)/(100-80)`
`t = (2.303)/(0.016)log 5`
`t = 100.6 MIN`


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