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Rate constant of a first order reaction A to B is 0.0693min^(-1). Calculate rate (i) at start and (ii) after 30 minutes. Initial concentration of A is 1.0M. |
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Answer» Solution :`k=0.0693min^(-1)` `t_((1)/(2))=(0.693)/(k_(1))=(0.693)/(0.0693)=10`min Since `C=C_(@)((1)/(2))^(n)` `n=(t)/(t_(1//2))` `n=(30)/(10)=3``C_(@)=1M` `:.C=1xx((1)/(2))^(3)=(1)/(8)M` Rate of the reaction at the START of the reaction `=k_(1)xxC_(@)`. `=10xx0.0693xx1=0.693M min^(-1)` Rate after `30`min `=k_(1)C=00693xx(1)/(8)=8.66xx10^(-8)M min^(-1)` |
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