1.

Rate expressionfor two reaction are : (a) "rate"_(a) = k_(a)[A] and (b) "rate"_(b) = k_(b) [B]^(2) . When[A] = [B] = 1 mol l^(-1) , k_(a) = k_(b) mol L^(-1). If [A] = [B] = 2 mol L^(-1) , write therelation between"rate"_(a)and "rate"_(b) .

Answer»

Solution :`"Rate"_(a)=k_(a)[2" mol L"^(-1)]`
`"Rate"_(B)=k_(b)["2 mol L"^(-1)]^(2)=k_(1)["2 mol L"^(-1)]^(2)`
The ration of the RATES of two REACTIONS (a) and (b) is given as, `("Rate"_(a))/("Rate"_(b))=(k_(a)["2 mol L"^(-1)])/(k_(a)["2 mol L"^(-1)]^(2))=1/2`
The ration of the rates = `1:2`.


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