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Rate= k[NO]^(2) [O_(2)]^(1). By how many times does the rate of reaction change when the volume of the reaction vessel is reduced to 1//3^(rd) of its original volume ? Will ther he any change in the order of the reaction. |
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Answer» Solution :`r_(1) = k[NO]^(2) [O_(2)]^(1), r_(2) = k[(NO)/(3)]^(2) [(O_(2))/(3)]^(1)` `r_(2) = 27r_(1)` Rate of reaction increases by 27 TIMES Order of the reaction REMAINS same. |
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