Rate of cooling of body is `0.5^(@)C`/min, when the system is `50^(@)C` above the surroundings. When a system is `30^(@)C` above the surroundings, the rate of cooling will beA. `0.3^(@)C`/minB. `0.6^(@)C`/minC. `0.7^(@)C`/minD. `0.4^(@)C`/min

Rate of cooling of body is `0.5^(@)C`/min, when the system is `50^(@)C

1.	Rate of cooling of body is `0.5^(@)C`/min, when the system is `50^(@)C` above the surroundings. When a system is `30^(@)C` above the surroundings, the rate of cooling will beA. `0.3^(@)C`/minB. `0.6^(@)C`/minC. `0.7^(@)C`/minD. `0.4^(@)C`/min
Answer» Correct Answer - A `(R_(2))/(R_(1))=(K(theta_(2)-theta_(1)))/(K(theta_(1)-theta_(0)))=(30)/(50)` `R_(2)=(3)/(5)R_(1)` `=(3)/(5)xx0.5=0.3.^(@)C//`min.

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Rate of cooling of body is `0.5^(@)C`/min, when the system is `50^(@)C` above the surroundings. When a system is `30^(@)C` above the surroundings, the rate of cooling will beA. `0.3^(@)C`/minB. `0.6^(@)C`/minC. `0.7^(@)C`/minD. `0.4^(@)C`/min

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