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Ratinalise the denominator3/4-√7 |
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Answer» There are multiple ways to go about doing this. The first method that I thought of is to start by looking at the fraction like so: 3–√−2(2+3–√)−7–√ From this, it makes SENSE to try multiplying the NUMERATOR and the denominator by (2+3–√)+7–√ , giving 3–√−2(2+3–√)−7–√×(2+3–√)+7–√(2+3–√)+7–√=23–√+3+21−−√−4−23–√−27–√(2+3–√)2−7=−1−27–√+21−−√43–√. |
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