1.

Rating of 12 V battery is 80 A, this means that if we join any conducting wire between two terminals of battery, we get 80 A electric current and internal resistance of battery = Omega.

Answer»

0
0.015
0.15
none of these

Solution :0.15
R= `(V)/(I) = (12)/(80) = 0.15 OMEGA`


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