InterviewSolution
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InterviewSolution
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Ratio of kinetic energy at mean position to potential energy at A/2 of a particle performing SHMA. ` 2:1`B. `4:1`C. `8:1`D. `1:1` |
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Answer» Correct Answer - B Kinetic energy `K=(1)/(2) momega^(2)(A^(2)-y^(2))` At mean position y=0 `K =(1)/(2) m omega^(2)(A^(2))` .... (i) Potential energy `U=(1)/(2) m omega^(2)y^(2)` `U " at " y=(A)/(2)` `U=(1)/(2)(mA^(2))/(4) omega^(2)` ......(ii) Dividing Eq (i) by Eq (ii) , we get `(KE)/(U)=(4)/(1)` |
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