1.

Ratio of masses of Na_(3)PO_(4) and Ca_(3)(PO_(4))_(2) each containing 31gm of P is ________

Answer»

<P>0.8
0.529
1.05
0.43

Solution :`n_(p)=n_(Na_(3)PO_(4))xx1 n_(Na_(3)PO_(4))xx2xxn_(Ca_(3))(PO_(4))_(2)`
`n_(p)=n_(Ca_(3))(PO_(4))_(2)xx2 (W_(Na_(3)PO_(4)))/(164)xx2xx(W_(Ca_(3))(PO_(4))_(2))/(310)`
`(W_(Na_(3)PO_(4)))/(W_(Ca_(3))(PO_(4))_(2))=(2xx164)/(310)=(328)/(310)=1.058`


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