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Ratio of the wavelength of first line of Lyaman series and first line of Balmer series isA. `1 : 3`B. `27 : 5`C. `5 : 27`D. ` 4 : 9` |
Answer» Correct Answer - C `(1)/(lambda) = R ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))` For first line of Lymen series `n_(1) = 1` and `n_(2) = 2` For first line of Balmer series `n_(2) = 2` and `n_(2) = 3` So, `(lambda_("Lymen"))/(lambda_("Balmen")) = (5)/(27)` |
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