Rationalise the denominator 1/(√3+√7+√5) – InterviewSolution

1.

Rationalise the denominator 1/(√3+√7+√5)

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Answer:

1/√3+√7+√5

=1/√3+√7+√5(√3+√7-√5/√3+√7-√5)

=√3+√7-√5/5+2√21

=(√3+√7-√5)(5-2√21)/-59

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