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Rationalise the denominator 1÷√7+√3-√2 |
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Answer» Multiply Numerator & DENOMINATOR by ( 7 + 3 )+( 2 )( 7 + 3 ) 2 −( 2 ) 2 ( 7 + 3 )+ 2 = 7+3+2 21 −27 + 3 + 2 = 8+2+ 21 7 + 3 + 2 Multiply Numerator & Denominator by (8−2 21 )= 64−84( 7 + 3 + 2 ) (8−2 21 )= −20(8 7 −2×7 3 +8 3 −2×3 7 +8) 2 −2 42 ) = −20(2 7 −6 3 +8 2 −2 42 ) = 206 3 −8 2 +2 42 −2 7 Step-by-step EXPLANATION:hope this helps u.please follow me |
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