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Ray of light is incident on surface of glass plate of absolute refractive index 1.55 at an angle of polarisation angle of refraction = ...... |
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Answer» `75^(@)11'`  `n=tantheta_(p)` `1.55=tan theta_(p)` `:.theta_(p)=tan^(-1)(1.55)` `:. Theta_(p)=57^(@)10.` From FIGURE, `theta_(p)+90^(@)+r=180^(@)` `:.theta_(p)+r=90^(@)` `:.r=90-theta_(p)` `:.r=89^(@)60.-57^(@)10.` `:. r=32^(@)50.` |
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