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Reaction between NO and O_(2)" to form "NO_(2)" is "2NO + O_(2) rarr2NO_(2) follows the following mechanism No + No k-1 N_(2) O_(2) (in rapid equilibrium) N_(2)O_(2) + O_(2) overset(k_(2))rarr 2NO_(2) (slow) Show that the rate of reaction is given by (1)/(2) ((d[NO_(2)])/(dt))=K[NO]^(2)[O_(2)] |
| Answer» SOLUTION :To PROVE | |