1.

Reaction : Cu_(("solid"))+2Ag_(("aqueous"))^(+) to Cu_(("aqueous"))^(2+)+2Ag_(("Solid")), what is the equilibrium constant for this reaction ? (E^(@)=0.46V" at "298K Temperature).

Answer»

`2.0xx10^(10)`
`4.0xx10^(10)`
`4.0xx10^(15)`
`2.4xx10^(10)`

Solution :Because `E_(cell)^(Theta)=(0.0591)/(N)logK_(c)`
`therefore 0.46=(0.0591)/(2)logK_(c)`
`therefore logK_(c)=(2xx0.46)/(0.0591)=15.57`
or `K_(c)="Antilog "15.57`
`=3.7xx10^(15)~~4xx10^(15)`.


Discussion

No Comment Found

Related InterviewSolutions