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Reaction is first order in A and second in B. How is the rate affected on increasing the concentration of B three times ? |
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Answer» Solution :If the concentration of B is increased three TIMES, then `(-d[R])/(DT)=k[A][3B]^(2)` `=9.k[A][3B]^(2)` `THEREFORE` The rate of reaction will increase 9 times. |
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