1.

Reaction is first order in A and second in B. How is the rate affected when the concentrations of both A and B are doubled ?

Answer»

Solution :When the concentrations of both A and B are doubled
`(-d[R])/(DT)=k[A][B]^(2)`
`=k[2A][2B]^(2)`
`= 8.k[A][B]^(2)`
`THEREFORE` The RATE of reaction will increase 8 TIMES.


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