1.

Reaction of KMnO_4 in neutral or very weakly acidic solution can be represented as

Answer»

`MnO_(4)^(-) + 2H_2O+3e^(-) RARR MnO_(2) + 4OH^(-)`
`2MnO_(4)^(-) + 2OH^(-) rarr 2MnO_(4)^(2-) + 1//2O_2 + H_2O`
`MnO_(4)^(-) + 8H^(+) + 5e^(-) rarr MN^(2+) + 4H_(2)O`
`MnO_(4)^(-)+ e^(-) rarr MnO_(4)^(2-)`

ANSWER :A


Discussion

No Comment Found

Related InterviewSolutions