1.

Reaction taking place at anode in Daneil cell

Answer»

`ZN^(2+) + 2 e to Zn(s)`
`Zn(s) to Zn^(2+) + 2 e`
`Cu + 2 e^(-) to Cu (s)`
`Cu(s) to Cu^(2+) + 2 e^(-)`

SOLUTION :Zn ACTS as ANODE and oxidised .
`E_(Cu^(2+) | Cu) gt E_(Zn^(2+) | Zn)`


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