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Reactions involving gold have been of particular interest to a chemist. Consider the following reactions, {:(Au (OH)_(3) + 4 HCl rarr HAuCl_(4) + 3 H_(2) O",",Delta H = - 28 k Cal,),(Au (OH)_(3) + HBr rarr HAuBr_(4) + 3 H_(2)O",",Delta H = -36.8 k Cal,):} In an experiment there was an absorption of 0.44 k Cal when one mole of HAuBr_(4) was mixed with 4 moles of HCl. what is the percentage conversion of HAuBr_(4) into HAuCl_(4) ? |
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Answer» 0.005 `HAuBr_(4)+4HCL rarr HAuCl_(4)+4HBr` `DeltaH=8.8` `%` CONVERSION `=100/8.8 xx0.44=5%` |
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