InterviewSolution
Saved Bookmarks
| 1. |
Reactions involving gold have been of particular interest to a chemist. Consider the following reactions, `{:(Au (OH)_(3) + 4 HCl rarr HAuCl_(4) + 3 H_(2) O",",Delta H = - 28 k Cal,),(Au (OH)_(3) + HBr rarr HAuBr_(4) + 3 H_(2)O",",Delta H = -36.8 k Cal,):}` In an experiment there was an absorption of 0.44 k Cal when one mole of `HAuBr_(4)` was mixed with 4 moles of `HCl`. what is the percentage conversion of `HAuBr_(4)` into `HAuCl_(4)` ?A. 0.005B. 0.006C. 0.05D. 0.5 |
|
Answer» Correct Answer - C Target reaction `HAuBr_(4)+4HCl rarr HAuCl_(4)+4HBr` `DeltaH=8.8` `%` conversion `=100/8.8 xx0.44=5%` |
|