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Rearrange the following compounds in increasing order of their boilig ponits: CH_(3)-CHO,CH_(3)CH_(2)-OH,CH_(3)-CH_(2)-CH_(3). |
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Answer» Solution :Due to EXTENSIVE intermolecular H-bonding, the b.p. of `CH_(3)CH_(2)OH` is the highest. Now `CH_(3)CHO` is polar while `CH_(3)CH_(2)CH_(3)` is non-polar. THEREFORE, due to dipole-dipole interactions, the b.p. of `CH_(3)CHO` is higher than that of `CH_(3)CH_(2)CH_(3)`. thus, the b.ps. of the three compounds INCREASE in the order: `CH_(3)CH_(2)CH_(3) LT CH_(3)CHO lt CH_(3)CH_(2)OH`. |
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