Redox reactins play a pivoted role in chemistry and biology. The values of standard redox potential (E^(@)) of two half-cell reactions decide which way the reaction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. Given below is a set of half-cell reactions (acidic medium) along with their E^(@) values with respect to normal hydrogen electrode. Using this data, obtained the correct explanations to questions 15-16 I_(2)+2e^(-)to2I^(-),E^(@)=1.36V Mn^(3+)+e^(-)toMn^(2+),E^(@)=1.50V Fe^(3+)+e^(-)toFe^(2+),E^(@)=0.77V O_(2)+4H^(+)+4e^(-)to2H_(2)O,E^(@)=1.23V Q. Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milliampere current. The time required to liberate 0.01 mole of H_(2) gas at the cathode is: (1 faraday =96500C)

Redox reactins play a pivoted role in chemistry and biology. The value

1.	Redox reactins play a pivoted role in chemistry and biology. The values of standard redox potential (E^(@)) of two half-cell reactions decide which way the reaction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. Given below is a set of half-cell reactions (acidic medium) along with their E^(@) values with respect to normal hydrogen electrode. Using this data, obtained the correct explanations to questions 15-16 I_(2)+2e^(-)to2I^(-),E^(@)=1.36V Mn^(3+)+e^(-)toMn^(2+),E^(@)=1.50V Fe^(3+)+e^(-)toFe^(2+),E^(@)=0.77V O_(2)+4H^(+)+4e^(-)to2H_(2)O,E^(@)=1.23V Q. Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milliampere current. The time required to liberate 0.01 mole of H_(2) gas at the cathode is: (1 faraday =96500C)
Answer» `9.65xx10^(4)sec` `19.3xx10^(4)sec` `28.95xx10^(4)sec` `38.6xx10^(4)sec` Solution :FARADAY LAW equivalents of `H_(2)` produced `=(Ixxt(sec))/(96500)` `0.01xx2=(10xx10^(3)XXT)/(96500)=96500xx2=t` `19.3xx10^(3)sec=t`