Redox reactions play a pivoted role in chemistry and biology. The values of standard redox potential and biology. The values of standard redox potential (E^0) of two half cell reactions decide which way the raction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. Given below are a set of half-cell reactions (acidic medium) along with their E^0 (V with respect to normal hydrogen eletrode ) values. Using this dat obtain the correct explanations to Questions I_2+2e^_ rarr2I^-E^0=0.54 Cl_2+2e^_ rarr2Cl^-E^0=1.36 Mn^(3+)+e^_ rarrMn^(2+)E^0=1.50Fe^(3+)+e^_ rarrFe^(2+)E^0=0.77O_2+4H^++4e^(-) rarr 2H_2OE^0=1.23While Fe^(3+) is stable, Mn^(3+) is not stable in acid soltuion because

Redox reactions play a pivoted role in chemistry and biology. The valu

1.	Redox reactions play a pivoted role in chemistry and biology. The values of standard redox potential and biology. The values of standard redox potential (E^0) of two half cell reactions decide which way the raction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. Given below are a set of half-cell reactions (acidic medium) along with their E^0 (V with respect to normal hydrogen eletrode ) values. Using this dat obtain the correct explanations to Questions I_2+2e^_ rarr2I^-E^0=0.54 Cl_2+2e^_ rarr2Cl^-E^0=1.36 Mn^(3+)+e^_ rarrMn^(2+)E^0=1.50Fe^(3+)+e^_ rarrFe^(2+)E^0=0.77O_2+4H^++4e^(-) rarr 2H_2OE^0=1.23While Fe^(3+) is stable, Mn^(3+) is not stable in acid soltuion because
Answer» `O_2` OXIDISES `MN^(2+)` to `Mn^(3+)` `O_2` oxidises both `Mn^(2+)` to `Mn^(3+)` and `FE^(2+)` to `Fe^(3+)` `Fe^(3+)` oxidises `H_2O " to " O_2` `Mn^(3+)` oxidises `H_2O " to " O_2` Answer :D