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Reduce the equation y+4=0 to the normal form `x cos alhpha+y sin alpha=p` and hence find the values of `alpha and p`. |
Answer» We have `y+4=0 Rightarrow -y=4" "["keeping constant positive"]` `Rightarrow x cos alpha+y sin alpha=p,"where cos "alpha=0,sin alpha=-1 and p=4` Now, `(cos alpha=0 and sin alpha=-1) Rightarrow alpha=270^(@)` Hence, the required normal form of hte given equation is `x cos 270^(@)+y sin 270^(@)=4` `"Clearly", alpha=270^(@) and p=4` |
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