1.

Reduction of acetyl chloride with H_(2) in presence of Pd gives

Answer»

`CH_(3)COCH_(3)`
`C_(2)H_(5)OH`
`CH_(3)COOH`
`CH_(3)CHO`

Solution :`CH_(3)COCl+H_(2)UNDERSET("REDUCTION")OVERSET(Pd)toCH_(3)CHO+HCl`


Discussion

No Comment Found