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Refer to figure `DeltaU_(1)` and `DeltaU_(2)` be the changes in internal energy in the system in process `A+B` and `DeltaW` be the net work done by the system in the process `A+B`, A. `DeltaQ-DeltaW=0`B. `DeltaQ+DeltaW=0`C. `DeltaU_(1)-DeltaU_(2)=0`D. `DeltaU_(1)+DeltaU_(2)=0` |
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Answer» Correct Answer - A::D As the system finally returns to its initial state, change in internal energy must be zero , i.e., `DeltaU=DeltaQ-DeltaW=0 or DeltaU=DeltaU_(1)+DeltaU_(2)=0` |
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