Refer to the arrangement of charges in shown figure and a Gaussian surface of radius R with Q at the centre. Then:

Refer to the arrangement of charges in shown figure and a Gaussian sur

1.	Refer to the arrangement of charges in shown figure and a Gaussian surface of radius R with Q at the centre. Then:
Answer» total flux through the surface of the sphere is `(-Q)/(4piepsilon_(0)R^(2))` field on the surface of the sphere is flux through the surface of sphere DUE to 5Q is zero. field on the surface of sphere due to -2Q is same everywhere. Solution :Charge enlosed by sphere, `=-2Q +Q` `=-Q` `therefore` flux associated with flux, `phi = -Q/epsilon_(0)` (`therefore` According to Gauss.s law) As SQ is outside, it doesn.tplay any role in flux.

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Refer to the arrangement of charges in shown figure and a Gaussian surface of radius R with Q at the centre. Then:

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