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Referring the graphs, which of the following is/are correc? A. (a) The particle has stable equilibrium at point 3 and b.B. (b) The particle is in neutral equilibrium at point b and 2.C. (c) No power is delivered by the force on the particle at point 1, 3, and b.D. (d) The particle has least kinetic energy at position 1. |
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Answer» Correct Answer - A::C::D Option (a) is correct because at 3, force is opposite to displacement. At (b), `u` is minimum. Option (b) is incorrect at 2, there is net force and hence no equilibrium. Option (c) is correct because at `1,3` and (b) force is zero. At (b), `(du)/(dx)=-F=0` Option (d) is correct. Positive work is done after position 1, hence KE will increase. So KE is least at 1. |
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