InterviewSolution
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InterviewSolution
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Referring to the previous illustration (a) What is the significance of positive and negative values of instantaneous velocities?(b) What are the distance covered and displacement during t= 2 sec? |
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Answer» Solution :(b) x=t(t-1)`rArr` v=2t-1`rArr`v=0at `t=1//2sec` Displacement =`OVERSET(2)underset(0)intvdt`=`overset(2)underset(0)int(2t-1)dt=(t^(2)-t)` `overset(2)underset(0)int=4-2=2m` Displacement=`overset(V2)underset(0)int|v|dt+overset(2)underset(v2)int|v|dt=(t^(2)-t)|_(0)^(v2)+|(t^(2)-t)|_(0)^(v2)+|=|(1)/(4)-(1)/(2)|+|4-2-(1)/(4)+(1)/(2)|rArr(1)/(4)+2(1)/(4)=2.5m` |
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