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Referring to the previous illustration, find the time of flight of the balls |
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Answer» Solution :`(T)^(2)={(2v_(0)sintheta_(0))/(G)}^(2)=(v_(0)^(2)sin^(2)theta)/(2g)(8)/(g)` `rArrT^(2)=(8H)/(g)` `rArrT=sqrt((8H)/(g))=2sqrt((2H)/(g))`: PutH=7.2m |
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