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Referring to the previous illustration what will be the induced e.m.f at any instant if the loop is rotated an axis passing through the centre and parallel to the length ? |
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Answer» Solution :The FLUX linked through the loop at any instant is `PHI` = BA COS `omega`t . `therefore` the induced e.m.f at any instant is `epsilon = (d phi )/(dt)` `RARR epsilon = -(d)/(dt)`(Blb cos `omega`t) `rArr epsilon = `+(Blb `omega"sin"omega`t) |
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