1.

Referring to the previous illustration what will be the induced e.m.f at any instant if the loop is rotated an axis passing through the centre and parallel to the length ?

Answer»

Solution :The FLUX linked through the loop at any instant is
`PHI` = BA COS `omega`t .
`therefore` the induced e.m.f at any instant is `epsilon = (d phi )/(dt)`
`RARR epsilon = -(d)/(dt)`(Blb cos `omega`t)
`rArr epsilon = `+(Blb `omega"sin"omega`t)


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