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Referring to the provious illustration, if the maximum heights for two possible paths are given as H_(1)=3m and H_(2)=9m, find the corresponding angles of projection |
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Answer» SOLUTION :`H_(1)//H_(2)=(v_(0)^(2)sin^(2)theta)/(2g)div(v_(0)^(2)sin^(2)(90-theta))/(2g)=tan^(2)theta` `rArrtheta=tan^(-1)sqrt((H_(1))/(H_(2)))=tan^(-1)[sqrt((3)/(9))]=.tan^(-1).(1)/(sqrt(3)=30^(@)` |
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